Re: Surprising parsing result with anonymous functions and for loops

[Mikael Magnusson <mikachu@xxxxxxxxx>]

On 25 September 2014 13:39, Peter Stephenson <p.stephenson@xxxxxxxxxxx> wrote:
> On Thu, 25 Sep 2014 12:02:55 +0200
> Mikael Magnusson <mikachu@xxxxxxxxx> wrote:
>> Okay, but does anyone at least agree that doing alias expansion at
>> that point is highly surprising?
>
> You mean regardless of function behaviour?
>
> % alias foo=bar
> % for i in 1; do : ; done foo
> zsh: parse error near `bar'

Ah, when i tested this i didn't realize it always happened, since i
tested with my ls alias (so the error said `ls' regardless). So yes
and no, it does happen regardless, but if you want to consider it a
feature that () for a { echo $a } ls works, then my meaning was that
it should at least print the exact arguments given.  :) ("you" in this
case being Bart, not actually you). I have nothing intelligent to say
about the rest of the mail except for nodding sagely while reading it,
so I'll elide it.

-- 
Mikael Magnusson