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Re: Can I do without "eval" here?

X-seq: zsh-users 10017
From: DervishD <zsh@xxxxxxxxxxxx>
To: zsh-users Mailinglist <zsh-users@xxxxxxxxxx>
Subject: Re: Can I do without "eval" here?
Date: Tue, 14 Mar 2006 10:42:49 +0100
In-reply-to: <20060314092235.GA9475@xxxxxxxxxxxxxxxxxxx>
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Organization: DervishD
References: <6F0CB04509C11D46A54232E852E390AC01004881@xxxxxxxxxxxxxxxxxxxxxxxxxx> <20060314091619.GA5940@DervishD> <20060314092235.GA9475@xxxxxxxxxxxxxxxxxxx>

    Hi Michal :)

 * Michal Politowski <mpol@xxxxxxxxxxxxxxxxxxx> dixit:
> On Tue, 14 Mar 2006 10:16:19 +0100, DervishD wrote:
> >     options=("-x")
> >     (($#)) && options=("-y" "$1")
> >     CMD $options[1] $options[2] foo
> 
> There is no need to split the array manually.
> CMD $options foo
> will do.

    Oops, my bad O:)) At first I didn't write the solution using an
array, and afterwards I just forgot that arrays don't need manual
splitting. Thanks for pointing :)

    Raúl Núñez de Arenas Coronado

-- 
Linux Registered User 88736 | http://www.dervishd.net
http://www.pleyades.net & http://www.gotesdelluna.net
It's my PC and I'll cry if I want to... RAmen!

References:
- Can I do without "eval" here?
  - From: Com MN PG P E B Consultant 3
- Re: Can I do without "eval" here?
  - From: DervishD
- Re: Can I do without "eval" here?
  - From: Michal Politowski

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